![At what point on the curve $$ y=[ln(x+4)]^2 $$ is the ta | Quizlet](https://d2nchlq0f2u6vy.cloudfront.net/21/08/31/a1543e011fd7856821b0cd05c853c358/5aa051cfbf74ecb52b41b5d12d109a6d/lateximg_large.png "At what point on the curve $$ y=[ln(x+4)]^2 $$ is the ta | Quizlet")
At what point on the curve $$ y=[ln(x+4)]^2 $$ is the ta | Quizlet
Solved Use logarithmic differentiation to find the | Chegg.com
=3x^{2}y-\sqrt{\ln(x-y^{2})}&line2=\mathrm{Solution:\:}\frac{dy}{dx}=\frac{12x^{2}y^{3}\sqrt{\ln(x-y^{2})}-12xy^{5}\sqrt{\ln(x-y^{2})}%2B12x^{2}y\sqrt{\ln(x-y^{2})}-12xy^{3}\sqrt{\ln(x-y^{2})}-y^{2}-1}{2(-y^{3}-y-y^{2}\sqrt{\ln(-y^{2}%2Bx)}%2Bx\sqrt{\ln(-y^{2}%2Bx)}-3x^{3}\sqrt{\ln(-y^{2}%2Bx)}%2B3x^{2}y^{2}\sqrt{\ln(-y^{2}%2Bx)}-3x^{3}y^{2}\sqrt{\ln(-y^{2}%2Bx)}%2B3x^{2}y^{4}\sqrt{\ln(-y^{2}%2Bx)})} "What is implicit derivative of (dy)/(dx),tan^{-1}(y)=3x^2y-sqrt(ln(x-y^2)) ? - Symbolab")
What is implicit derivative of (dy)/(dx),tan^{-1}(y)=3x^2y-sqrt(ln(x-y^2)) ? - Symbolab
calculus - Show that $z = \ln (x^2+y^2) +2\tan^{-1}(y/x)$ satisfies the laplaces's equation. - Mathematics Stack Exchange
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![Integral of ln( [3]sqrt(x) ) (by parts) - YouTube](https://i.ytimg.com/vi/yCvXVdTAhCg/maxresdefault.jpg "Integral of ln( [3]sqrt(x) ) (by parts) - YouTube")
Integral of ln( [3]sqrt(x) ) (by parts) - YouTube
}&line2=\mathrm{Solution:\:}x%3C-2\lor%20-2%3Cx%3C-\sqrt{3}\lor%20\sqrt{3}%3Cx%3C2\lor%20x%3E2 "domain of y=(sqrt(x^2-3))/(ln(x^2-3)) - Symbolab")
domain of y=(sqrt(x^2-3))/(ln(x^2-3)) - Symbolab
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ln(x)=1
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Integral of ln(x)/sqrt(x) (by parts) - YouTube
Derivative Rules
5. Derivative of the Logarithmic Function
